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Company Profile - PT. Abhimata Persada

Muhamad Royyan Zulfalah (53417809) Tugas Pengantar Bisnis Informatika 4IA13 PT. Abhimata Persada IT Solution Provider for Banking & Financial Industries Company Background PT Abhimata Persada was established in 1990 in Jakarta in order to respond to the growing needs of Indonesia's banking and telecommunication sector. Since then we have been steadily building up a strong local presence backed by proven skills and expertise of our personnel. Currently, Abhimata Persada has grown to be an IT company with significant supporting role in Indonesia's banking sector. Our more than 120 associates are working full time in each and every specific need of the financial institution, especially in banking industry, from advisory, supporting role to the role of implementer. It is our aim to develop long-term partnerships with clients, to ensure continuity and reliability of service to them. Our clients are active in a range of market, from the telecommunicati...

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Relasi Rekursif Matematika Informatika

Soal Matematika Informatika Tentang Relasi Rekursif 1. Diketahui suatu barisan c0, c1, c2, … didefinisikan secara rekursif sebagai berikut : Untuk semua bilangan bulat k ≥ 2, Ck = (ck-1 + k) (ck-2 + 1). Dengan kondisi awal c0 = 1 dan c1 =2. Ditanya : Hitunglah c5 ! Pembahasan : Oleh karena barisan didefinisikan secara rekursif, maka c5 tidak bias dihitung secara langsung, tetapi harus terlebih dahulu menghitung c2, c3 dan c4. c2 = c1 + 2 c0 + 1 = 2 + 2.1 + 1 = 5 c3 = c2 + 3 c1 + 1 = 5 + 3.2 + 1 = 12 c4 = c3 + 4 c2 + 1 = 12 + 4.5 + 1 = 33 c5 = c4 + 5 c3 + 1 = 33 + 5.12 + 1 = 94 Jadi, c5 = 94 2 . Solusi homogen dari relasi rekurensi bn + bn-1 – 2 bn-2 = 0 dengan kondisi batas b0 = 2 , b1 = 3 adalah… Pembahasan : bn + bn-1 – 2 bn-2 = 0 = a2 + a- 2 = 0 = (a+ 2) (a- 1) = 0 a1 = -2 a2 = 1. Solusi homogen = bn(h)= A1 a1n+ A2 a2n =>bn(h)= A1 (-2)n+ A2 . (1)n Dengan kondisi batas ...

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